The key would be releasing stored energy in the form of chemical or molecular bonds. I once got more energy out of a system than I put in, if you consider that all I did was add water to Drano crystals. A chemical reaction occurred that created heat, lots of it (I used too much Drano in Chem lab than I was supposed to when making lye soap). The drain I poured that mixture down, in order to get rid of it before it did something bad, smoked for a bit. It never did back up again though.
Brian
-----Original Message----- From: Billy Crook Sent: Tuesday, September 11, 2007 3:47 PM
You can not get more energy out of a system than you put in to it. There are NO exceptions, Get over it. The best you can hope for is 100% efficiency, and that would still only be a hope.
On 9/11/07, Jon Pruente [email protected] wrote:
On 9/11/07, Jonathan Hutchins [email protected] wrote:
The energy required for the RF input (that according to most of the articles "breaks down" the salt water) is the question - does it
take more
energy to provide that RF than the "flame" produces - or than can be recovered from the flame. (Remember, a flame in itself isn't a very
useful
source of energy, and there are considerable losses converting it to electricity or other useful forms.)
From what I've seen elsewhere it does take more energy to produce the RF than is released by the reaction. It seems to be basically super heating the water so that the hydrogen and oxygen split, then when the atoms leave the area being excited, they "burn" and come back together as water again, with a net loss of energy from waste heat.
Jon.